24x^2+116x-20=0

Solution for 24x^2+116x-20=0 equation:

24x^2+116x-20=0

a = 24; b = 116; c = -20;
Δ = b2-4ac
Δ = 1162-4·24·(-20)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(116)-124}{2*24}=\frac{-240}{48}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(116)+124}{2*24}=\frac{8}{48}
=1/6
$